Answer: 0.1506 moles of HS2
Explanation:To determine the number of moles of HS2 formed from 50g of KI, we need to follow these steps:
1. Find the molar mass of KI:
- The molar mass of K (potassium) is approximately 39.10 g/mol.
- The molar mass of I (iodine) is approximately 126.90 g/mol.
- Add the molar masses of K and I to get the molar mass of KI:
39.10 g/mol + 126.90 g/mol = 166.00 g/mol.
2. Calculate the number of moles of KI in 50g:
- Use the formula: Number of moles = Mass (g) / Molar mass (g/mol).
- Number of moles of KI = 50g / 166.00 g/mol ≈ 0.3012 mol.
3. Determine the mole ratio between KI and HS2:
- The balanced chemical equation is needed for this step. Let's assume the reaction is:
2 KI + H2SO4 → 2 KHSO4 + I2
- From the equation, we see that 2 moles of KI react to form 1 mole of HS2.
4. Calculate the number of moles of HS2 formed:
- Using the mole ratio from the balanced equation, we find:
Number of moles of HS2 = 0.3012 mol KI × (1 mol HS2 / 2 mol KI) = 0.1506 mol HS2.
Therefore, from 50g of KI, approximately 0.1506 moles of HS2 will be formed based on the given reaction.
