Respuesta :
Nice! Now, the slope of the line joining points (-1, 2) and (5, -4) is
[tex]m=\frac{-4-2}{5-(-1)}=\frac{-6}{6}=-1[/tex]
Look at each answer choice and pick out the one that has a slope of -1.
a. y = -x + 1 The coefficient of x is -1, so that's the answer you want.
b. y = -1/3x - 4 The coefficient of x is -1/3; the slope is -1/3. Nope.
etc.
[tex]m=\frac{-4-2}{5-(-1)}=\frac{-6}{6}=-1[/tex]
Look at each answer choice and pick out the one that has a slope of -1.
a. y = -x + 1 The coefficient of x is -1, so that's the answer you want.
b. y = -1/3x - 4 The coefficient of x is -1/3; the slope is -1/3. Nope.
etc.
Answer:
y=-x+1
Step-by-step explanation:
find equation of a line parallel to the line that passes through the points (-1, 2) and (5, -4)
Equation of a line is y=mx+b
where m is the slope and b is the y intercept
[tex]m=\frac{y2-y1}{x2-x1} = \frac{-4-2}{5+1} = -1[/tex]
m= -1 , parallel line has same slope
to find out b we plug in (-1,2) in y=mx+b
2= -1(-1) +b
2=1+b
Subtract 1 from both sides
b= 1
So equation of line is y=-1x+1
y=-x+1