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17-08-2017
Mathematics

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Evaluate 27 with and exponent of -5/3

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17-08-2017

[tex]x^{-m}=\frac{1}{x^m}[/tex]
and
[tex](x^m)^n=x^{mn} [/tex]
so
[tex]27^\frac{-5}{3}=(3^3)^\frac{-5}{3}=3^\frac{-15}{3}=3^{-5}=[/tex] [tex]\frac{1}{3^5}=\frac{1}{243}[/tex]

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