18-05-2015
Mathematics

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Y^2-y=2 how do you solve?

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Panoyin Panoyin

18-05-2015

   y² - y = 2
y² - y - 2 = 2 - 2
y² - y - 2 = 0
y = -(-1) +/- √((-1)² - 4(1)(-2))
   2(1)
y = 1 +/- √(1 + 8)
      2
y = 1 +/- √(9)
      2
y = 1 +/- 3
   2
y = 1 + 3 or y = 1 - 3
   2 2
y = 4    y = -2
      2    2
y = 2    y = -1

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