17-05-2015
Mathematics

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how would you solve 3sin0=sin0-1

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17-05-2015

I would subtract 1sin(Θ) from each side of the equation.
The equation would then say that 2sin(Θ) = -1 .
I would only have to find angles whose sin is -1/2 ,
and those would be my solutions.

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Panoyin Panoyin

17-05-2015

   3sinΘ = sinΘ - 1
3sinΘ - sinΘ = sinΘ - sinΘ - 1
   2sinΘ = -1
      2sin    2sin
       Θ = -2.864934497

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