Answer:
(-3/2, 0), (1, 0) and (4, 0)
Step-by-step explanation:
Given polynomial is y = (2x+3)(x-1)(x-4
The x intercepts are the x-values where the graph of the polynomial intersects the x-axis. At these points y = 0
Setting the polynomial function to 0 allows us to find these intercepts
y = 0 ==> (2x + 3)(x - 1)(x-4) = 0
Setting each factor equal to zero, we get:
2x + 3 = 0 which gives 2x = -3, x = -3/2
x - 1 = 0 giving x = 1
x -4 = 0 giving x = 4
So the x-intercepts are at points (-3/2, 0), (1, 0) and (4, 0)
