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-28.1 x 10C 91 Find the net force on q2. 0.300 m F, +25.5x 10c + 92 Fj- [?]N 0.300 m- = force exerted on q2 by q1 F = force exerted on q2 by q3 Remember: Like charges repel; opposite charges attract. -47.9 x 10C N​

Respuesta :

Answer:

Explanation:

Given:

q1 = -28.1 x 10^(-9) C

q3 = +25.5 x 10^(-9) C

F = (k * |q1 * q2|) / r^2

F1 = (9 x 10^9 N m^2/C^2) * (|-28.1 x 10^(-9) C * q2|) / (0.300 m)^2

F3 = (9 x 10^9 N m^2/C^2) * (|+25.5 x 10^(-9) C * q2|) / (0.300 m)^2

q2 = F1 + F3

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