To find the concentration of the original HBr solution, we can use the equation:
M1V1 = M2V2
where M1 is the concentration of the original HBr solution, V1 is the volume of the original HBr solution, M2 is the concentration of the Sr(OH)2 solution, and V2 is the volume of the Sr(OH)2 solution.
Plugging in the given values:
(25.0 mL)(M1) = (0.105 M)(14.1 mL)
Solving for M1:
M1 = (0.105 M)(14.1 mL) / 25.0 mL
M1 ≈ 0.0594 M
Therefore, the concentration of the original HBr solution is approximately 0.0594 M.
