The first linear equation in a system has a slope of –4 and a y-intercept of 2. The second linear equation has a slope of –2 and passes through the point (3, –2). What is the solution to the system of equations? (–1, 6) (1, 6) (0, 5) (0, 2)

Respuesta :

Answer:

(-1, 6)

Step-by-step explanation:

The equation of a line in slope-intercept form is
y = mx + b

where m = slope and b = y-intercept

The equation of the first line is
y = -4x + 2     (1)


For the second line we are not given the y-intercept only the slope.
y = --2x + b

However we are told it passes through (3, -2)
Substitute -2 for y and 3 for x to solve for b
- 2 = -2(3) + b
-2 = -6 + b

6 - 2 = b  (subtract 6 both sides)
4 = b or b = 4

Second line equation is y = -2x + 4   (2)

Since left side of both (1) and (2) is y we can set the right sides equal to each other and solve

-2x + 4 = -4x + 2

Add 4x both sides:
4x - 2x + 4 = 2

2x + 4 = 2

Subtract 4 both sides:
2x = 2 - 4 = -2

Divide by 2 both sides:
x = -1

Only one answer choice has x = -1 so the solution is (-1, 6)

We could solve for y using x = -1 in any of the two equations. It will turn out to be 6

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