Respuesta :
Answer:
2.585 m/s
Explanation:
To find the speed of the skateboard-cat combination, we can use the principle of conservation of momentum.
The principle of conservation of momentum states that the total momentum before an event is equal to the total momentum after the event, assuming there are no external forces acting on the system.
In this case, the initial momentum of the skateboard-cat combination is the momentum of the skateboard alone, since the cat is initially at rest. The final momentum is the momentum of the skateboard-cat combination after the cat lands on it.
The momentum of an object is given by the product of its mass and velocity.
Let's denote the initial velocity of the skateboard as v1 and the final velocity of the skateboard-cat combination as v2.
The initial momentum of the skateboard is given by the product of its mass (1.12 kg) and velocity (4.44 m/s):
Initial momentum = mass of skateboard × initial velocity = 1.12 kg × 4.44 m/s
Since the cat is initially at rest, its initial momentum is zero.
The final momentum of the skateboard-cat combination is the sum of the momenta of the skateboard and the cat. We need to calculate the velocity of the cat before we can calculate the final momentum.
To do this, we can use the conservation of momentum equation:
Initial momentum = Final momentum
(1.12 kg × 4.44 m/s) + (0 kg × 0 m/s) = (1.12 kg + 0.80 kg) × v2
Simplifying the equation:
4.9648 kg·m/s = 1.92 kg × v2
Dividing both sides of the equation by 1.92 kg:
v2 = 4.9648 kg·m/s / 1.92 kg
v2 ≈ 2.585 m/s
Therefore, the speed of the skateboard-cat combination is approximately 2.585 m/s after the cat drops onto the skateboard.
