My character has a 45.8% chance to dodge the attack from the enemy character and a 43.82% chance to block it. additionally, both effects can trigger at the same time. if either one of them activates, i won't receive any damage, just as if both of them activate. what is the probability of taking damage in the event of an attack

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Answer:

To calculate the probability of taking damage, you can use the complement rule, which states that the probability of an event happening is equal to 1 minus the probability of the event not happening.

Let \( P(D) \) be the probability of taking damage.

The probability of dodging the attack is \( P(\text{Dodge}) = 0.458 \).

The probability of blocking the attack is \( P(\text{Block}) = 0.4382 \).

Since both effects can trigger at the same time, and if either one of them activates, you won't receive any damage, the probability of not taking damage is the complement of the probability of taking damage.

\[ P(\text{Not Taking Damage}) = 1 - P(D) \]

\[ P(\text{Not Taking Damage}) = 1 - (P(\text{Dodge}) \times P(\text{Block})) \]

\[ P(\text{Not Taking Damage}) = 1 - (0.458 \times 0.4382) \]

[ P(\text{Not Taking Damage}) = 1 - 0.2004536 \

[ P(\text{Not Taking Damage}) = 0.7995464 \]

Therefore, the probability of taking damage (\( P(D) \)) is approximately \( 1 - 0.7995464 = 0.2004536 \), or 20.05%.

Step-by-step explanation:

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