PLESE HELP ME!!!

5. The two given triangles are similar.
4 cm
у ст
20 cm
30 cm
Find the missing length y, rounding to 1 decimal place if necessary.

all the things you need to answer is in the picture

PLESE HELP ME 5 The two given triangles are similar 4 cm у ст 20 cm 30 cm Find the missing length y rounding to 1 decimal place if necessary all the things you class=

Respuesta :

Answer:

[tex] \frac{4}{y} = \frac{20}{30} [/tex]

[tex]20y = 120[/tex]

[tex]y = 6[/tex]

msm555

Answer:

y = 6 cm

Step-by-step explanation:

To find the missing length [tex] y [/tex] in the similar triangles, we can set up a proportion using the corresponding sides.

Since, in similar triangles the corresponding sides are proportional.

The given proportion is:

[tex] \dfrac{4}{20} = \dfrac{y}{30} [/tex]

Now, cross-multiply to solve for [tex] y [/tex]:

[tex] 4 \times 30 = 20 \times y [/tex]

[tex] 120 = 20y [/tex]

Now, divide by 20 to find [tex] y [/tex]:

[tex] y = \dfrac{120}{20} [/tex]

[tex] y = 6 [/tex]

So, the missing length [tex] y [/tex] is 6 cm.

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