Respuesta :

tiara143
The inequality is : 26 + 6b= 2(3b + 4)
On opening the bracket we get,
or 26 + 6b= 6b + 8
Now, bring the variable terms to right hand side,
or 26 + 6b - 6b = 8
or 26 = 8, which is not possible because 26 can never be equal to 8.
Thus, this inequality has no solutions. 
calculista

we have

[tex]26 + 6b\geq2(3b + 4)[/tex]

Applying the distributive property on the right side

[tex]26 + 6b\geq6b+8[/tex]

subtract [tex]6b[/tex] from both sides

[tex]26\geq 8[/tex] -------> is true

for all real numbers the inequality is true

therefore

the graph is a shaded area everywhere.

the answer is

the solution is all real numbers

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