Hiram raises earthworms. In a square of compost 4 ft by 4 ft, he can have 1000 earthworms. How many earthworms can he have if his square of compost has a side length that is 8 times longer?
A. 8000
B. 64,000
C. 256,000
D. 32,000

hmm, find the area

area=length times widtha
rea=4 times 4=16 square feet

so every 16 square feet is 1000 earthworms
so ratio of worms to area is 1000:16

if each side length is 8 then
8 times 8=64 area
but how many worms?

1000:16=?:64
1000/16=?/64
times both sides by 64
64000/16=?
4000=?
wat, not listed? why

if we assume it's a cube then
voluem is 4^3 or 64
1000:64 is the ratio

if 8ft then 8^3=512
so
1000:64=?:512
1000/64=?/512
512000/64=?
8000=?

I guess it was a cube then
A would be the answer

Hiram raises earthworms. In a square of compost 4 ft by 4 ft, he can have 1000 earthworms. How many earthworms can he have if his square of compost has a side length that is 8 times longer? A. 8000 B. 64,000 C. 256,000 D. 32,000

Respuesta :

Otras preguntas

Hiram raises earthworms. In a square of compost 4 ft by 4 ft, he can have 1000 earthworms. How many earthworms can he have if his square of compost has a side length that is 8 times longer?
A. 8000
B. 64,000
C. 256,000
D. 32,000