Answer:
Option D
Step-by-step explanation:
We are given an angle as
[tex]\theta =\frac{7\pi }{4}[/tex]
This angle lies between 3pi/2 and 2pi
i.e. in IV quadrant
In Iv quadrant only cos and secant are positive
sine and tangent would be negative
The principal value is pi/4 and for this tan =1
Hence we have
sin Θ = negative square root 2 over 2; cos Θ = square root 2 over 2; tan Θ = −1
Option D is right
