tluu03
tluu03
20-06-2017
Mathematics
contestada
Find the remainder for (b3 − 5b2 − 2b + 8)⎟(b − 4).
Respuesta :
mergl
mergl
20-06-2017
(b^3-5b^2-2b+8)/((b-4)
(b^2)(b^3-5b^2-2b+8-b^3+4b^2)
(b^2)(-1b^2-2b+8)
(b^2-b)(-1b^2-2b+8+b^2-4b)
(b^2-b)(-6b+8)
(b^2-b-6)(-6b+8+6b-24)
(b^2-b-6)(-16)
Remainder=-16
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