Respuesta :

The answer is choice C. 

The hole is attached to the graph for x^2+4 which means that we do NOT include this as part of the graph. The graph x^2+4 is only graphed when x < 2 is true which is what choice C says. Similarly, x+4 is only graphed when x >= 2.

Answer:

The correct option is C. [tex]y=\left \{ {x^2+4, \; x<2} \atop {x+4, \;x\geq 2}} \right.[/tex]

Step-by-step explanation:

Consider the provided graph:

The graph has an open and closed dot at x = 2.

The open dot attached to the function [tex]y=x^{2}+4[/tex] and the closed dot attached to the function [tex]y=x+4[/tex].

Note, we use [tex]\leq or \geq[/tex] sign in order to show closed dots and < or > sign to show open dots.

By observing the graph, it is clear that the function [tex]y=x+4[/tex] takes all the value which are greater or equal to 2. Therefore, the function can be written as [tex]y=x+4, x\geq 2[/tex].

The graph of the function [tex]y=x^{2}+4[/tex] has an open dot at [tex]x = 2[/tex] which means the function can take all real values less than 2. Therefore, the function can be written as [tex]x^2+4, x<2[/tex].

Therefore, the correct option is C. [tex]y=\left \{ {x^2+4, \; x<2} \atop {x+4, \;x\geq 2}} \right.[/tex]

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