△XYZ was reflected over a vertical line, then dilated by a scale factor of 1/2, resulting in △X'Y'Z'. Which must be true of the two triangles? Check all that apply.

△XYZ ~ △X'Y'Z'
XZY ≅ Y'Z'X'
YX ≅ Y'X'
XZ = 2X'Z'
mYXZ = 2mY'X'Z'

Given that the triangle XYZ was reflected over a vertical line, then dilated by a scale factor of 1/2, resulting in triangle X'Y'Z'. The true statement is:
triangle XYZ is similar to X'Y'Z
YX is similar Y'X'
XZ=2X'Z'
The above are the true statements.

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AFOKE88 AFOKE88 · Answer 2 · 2022-05-04T11:56:05+02:00

The options that are true about the two triangles are; △XYZ ~ △X'Y'Z';

XZY ≅ Y'Z'X' and XZ = 2X'Z'

How to Solve Transformation Problems?

W are told that △XYZ is reflected over a vertical line, then dilated by 1/2 to form X'Y'Z'. This means that;

X'Y'Z' = ¹/₂XYZ

i.e. the side lengths of triangle X'Y'Z' is half the side lengths of the original triangle XYZ

Thus, we can say that:

The triangles are similar

The angles are congruent.

The side lengths of XYZ are twice the side lengths of X'YZ'.

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△XYZ was reflected over a vertical line, then dilated by a scale factor of 1/2, resulting in △X'Y'Z'. Which must be true of the two triangles? Check all that apply. △XYZ ~ △X'Y'Z' XZY ≅ Y'Z'X' YX ≅ Y'X' XZ = 2X'Z' mYXZ = 2mY'X'Z'

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How to Solve Transformation Problems?

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△XYZ was reflected over a vertical line, then dilated by a scale factor of 1/2, resulting in △X'Y'Z'. Which must be true of the two triangles? Check all that apply.

△XYZ ~ △X'Y'Z'
XZY ≅ Y'Z'X'
YX ≅ Y'X'
XZ = 2X'Z'
mYXZ = 2mY'X'Z'