Answer:
Correct choice is C
Step-by-step explanation:
Consider triangle PQR. In this triangle PQ=17 units, QR=15 units and PR=14 units. Angle P is opposite to the side QR. Use the cosine law to determine the cosine of the angle P:
[tex]QR^2=PR^2+QP^2-2\cdot PQ\cdot PR\cdot \cos \angle P,\\ \\15^2=17^2+14^2-2\cdot 17\cdot 14\cdot \cos \angle P,\\ \\225=289+196-476\cos \angle P,\\ \\-476\cos \angle P=225-289-196,\\ \\-476\cos \angle P=-260,\\ \\\cos \angle P=\dfrac{260}{476}=\dfrac{65}{119},\\ \\\angle P\approx 57^{\circ}.[/tex]
The measure of P is 57 degrees.
Given
The measure of the Side PQ is 17, QR is 15, and PR is 14.
The cosine rule, in trigonometry, is used to find the sides and angles of a triangle.
The cosine rule is also called the law of cosine.
Angle P is opposite to the side QR.
Therefore,
The measure of p is;
[tex]\rm QR^2=PR^2+QP^2-2\times PQ \times PR \times Cos \angle p\\\\15^2=17^2+14^2- 2\times 17 \times 14Cos \angle p\\\\ 225=289+196-476 Cos\angle p\\\\ 225=485- 476Cos\angle p\\\\ 225-485 =-476 Cos\angle p\\\\ -260=-476Cos \angle p\\\\Cos \angle p= \dfrac{-476}{-260}\\\\Cos\angle p = 1.83\\\\\angle P = 57 \ degrees[/tex]
Hence, the measure of P is 57 degrees.
To know more about the Cosine rule click the link given below.
https://brainly.com/question/14290164
