The bottom of a 12-foot ladder is placed on the ground 7 feet from the base of a pipe sticking out of the ground. The top of the ladder is placed an unknown distance off the ground, leaning on the pipe. The ladder and the ground meet at a 56.4° angle. At what angle does the pipe meet the ground?

Respuesta :

Let x = length of pipe.
Use Law of Cosines to find x: x^2 = 7^2 + 12^2 -2(7)(12)cos(56.4) = 98.03; x=9.901.
Let y = angle between pipe and ground.
Use Law of Sines to calculate y.
sin y/12 = sin(56.4)/9.901 ; sin y = 1 (approx). y = 90 deg.
 Answer: 90 deg.

Answer:

D 87.9

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