Answer:
[tex]V_2=4.60L[/tex]
Explanation:
Hello,
In this case, by means of the Boyle's law which allows us to understand a gas' volume-pressure relationship through an inversely proportional relationship:
[tex]P_1V_1=P_2V_2[/tex]
We solve for the final volume [tex]V_2[/tex] as required, including the conversion from mmHg to atm for the final pressure:
[tex]V_2=\frac{P_1V_1}{P_2} =\frac{1.50atm*5.00L}{1240mmHg*\frac{1atm}{760mmHg} } \\\\V_2=4.60L[/tex]
Regards.
