Respuesta :

At critical angle,
[tex]\sin{45.5} = \frac{1}{n_{l}}[/tex]
so
[tex]n_{l} = 1.4 [/tex]

The index of refraction of the liquid is mathematically given as

n=1.4

What is the index of refraction of the liquid?

Question Parameter(s):

The critical angle for a certain liquid-air surface is 45.5 ∘ .

Generally, the equation for the  at a critical angle ,  is mathematically given as

sin45=1/n

Therefore

n=1.4

In conclusion, the index of refraction of the liquid

n=1.4

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