Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x. (
a. Use a linear approximation to estimate g(2.99) and g(3.01).

So it tells us that g(3) = -5 and g'(x) = x^2 + 7.

So g(3) = -5 is the point (3, -5)
Using linear approximation
g(2.99) is the point (2.99, g(3) + g'(3)*(2.99-3))

now we just need to simplify that
(2.99, -5 + (16)*(-.01)) which is (2.99, -5 + -.16) which is (2.99, -5.16)
So g(2.99) = -5.16

Doing the same thing for the other g(3.01)
(3.01, g(3) + g'(3)*(3.01-3))
(3.01, -5 + 16*.01) which is (3.01, -4.84)
So g(3.01) = -4.84

So we have our linear approximation for the two.

If you wanted to, you could check your answer by finding g(x). Since you know g'(x), take the antiderivative and we will get
g(x) = 1/3x^3 + 7x + C
Since we know g(3) = -5, we can use that to solve for C
1/3(3)^3 + 7(3) + C = -5 and we find that C = -35
so that means g(x) = (x^3)/3 + 7x - 35

So just to check our linear approximations use that to find g(2.99) and g(3.01)

g(2.99) = -5.1597
g(3.01) = -4.8397

So as you can see, using the linear approximation we got our answers as
g(2.99) = -5.16
g(3.01) = -4.84
which are both really close to the actual answer. Not a bad method if you ever need to use it.

abidemiokin abidemiokin · Answer 2 · 2021-10-19T15:32:11+02:00

The estimated value of g(2.99) and g(3.01) are -5.1597 and -4.8397 respectively

Given the expression g'(x) = x² + 7

[tex]\frac{dy}{dx} = x^2 + 7\\dy = (x^2+7)dx[/tex]

Integrate both sides of the expression:

[tex]\int dy = \int\ ({x^2+7}) \, dx \\y= \int\ ({x^2+7}) \, dx \\y=\frac{x^3}{3} + 7x + C\\g(x) = \frac{x^3}{3} + 7x + C\\[/tex]

If g(3) = −5, hence;

[tex]g(x) = \frac{x^3}{3} + 7x + C\\-5= \frac{3^3}{3} + 7(3) + C\\-5 = \frac{27}{3} + 21 + C\\-5 = 30 +C\\C = -35[/tex]

The function g(x) will then be expressed as:

[tex]g(x) = \frac{x^3}{3} + 7x - 35\\[/tex]

Next is to get the value of g(2.99) and g(3.01)

[tex]g(2.99) = \frac{(2.99)^3}{3} + 7(2.99) - 35\\g(2.99) = 8.910299 + 20.93 - 35\\g(2.99) = -5.1597\\\\[/tex]

Similarly for g(3.01)

[tex]g(3.01) = \frac{(3.01)^3}{3} + 7(3.01) - 35\\g(3.01) = 9.0903+ 21.07 - 35\\g(3.01) = -4.8397\\[/tex]

Hence the estimated value of g(2.99) and g(3.01) are -5.1597 and -4.8397 respectively

Learn more here: https://brainly.com/question/23733601

Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x. ( a. Use a linear approximation to estimate g(2.99) and g(3.01).

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Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x. (
a. Use a linear approximation to estimate g(2.99) and g(3.01).