Answer:
Speed of the ball when it hits the ground, v = 7.7 m/s
Explanation:
It is given that,
Mass of the brick, m = 5 kg
It is released at a height of, s = 3 m
We need to find the speed with which it hits the ground. It can be calculated using the third equation of motion as :
[tex]v^2-u^2=2as[/tex]
Here, a = g and u = 0
[tex]v^2-u^2=2gs[/tex]
[tex]v=\sqrt{2gs}[/tex]
[tex]v=\sqrt{2\times 9.8\times 3}[/tex]
v = 7.668 m/s
or
v = 7.7 m/s
So, the velocity of the ball when it hits the ground is 7.7 m/s. Hence, this is the required solution.
