willpoyner willpoyner

19-06-2017
Mathematics

contestada

solve for a 5/a - 2/1-a = 2/a-1
a=0
a=-1
a=1
none

Respuesta :

ghanami ghanami

19-06-2017

hello :
[tex] \frac{5}{a} - \frac{2}{1-a} = \frac{2}{a-1} = \frac{5}{a}+ \frac{2}{a-1} = \frac{2}{a-1} = \frac{5(a-1)+2a}{a(a-1)} = \frac{2a}{a(a-1)} (a \neq 1 , a \neq 0) [/tex]
5a-5 +2a =2a
5a =5
a=1 ( refused)
conclusion : none

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