Line AB passes through points A(–6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y = mx + b, then m = – and b = –6–55 6.
y = mx + b slope(m) = -1/6 use either of ur points (12,3)....x = 12 and y = 3 now sub and find b, the y int 3 = -1/6(12) + b 3 = -12/6 + b 3 = -2 + b 3 + 2 = b 5 = b
