Answer: n ≤ − the quantity 7 times c minus 25 all over p
Step-by-step explanation:
Given inequality: [tex]-np-3\geq7(c-4)[/tex]
First open parentheses, and solve the right side of the inequality.
[tex]-np-3\geq7c-28[/tex]
Add 3 on both sides, we get
[tex]-np\geq7c-25[/tex]
Divide -p on both sides (sign will reverse), we get
[tex]n\leq-\frac{7c-25}{p}[/tex]
Thus the answer is n ≤ − the quantity 7 times c minus 25 all over p.
