This is my next Trigonometry question I am needed help on- I just want to be sure I've got it right, or if not, then the steps I need to take to get it right. Thank you.

This is my next Trigonometry question I am needed help on I just want to be sure Ive got it right or if not then the steps I need to take to get it right Thank class=

Respuesta :

[tex]\bf \begin{array}{clclll} (-6&,&-8)\\ x&&y\\ a&&b \end{array}\qquad c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \\\\\\ c=\sqrt{(-6)^2+(-8)^2}\implies c=\sqrt{100}\implies c=10\impliedby \begin{array}{llll} c\ is\ never\\ negative \end{array} \\\\\\ sin(\theta)=\cfrac{opposite}{hypotenuse}\implies sin(\theta)=\cfrac{-8}{10} \\\\\\ sin(\theta)=-\cfrac{4}{5}[/tex]
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