contestada

When the function f(x) = 6(9)x is changed to f(x) = 6(9)x + 1, what is the effect?

There is no change to the graph because the exponential portion of the function remains the same.
All input values are moved 1 space to the right.
The x-intercept is 1 space higher.
The y-intercept is 1 space higher.

Respuesta :

BeautifulAfflictions
The answer would be:
The y-intercept is 1 space higher.

This equation is a y=mx+b and if you didn't already know, the +b is the y-intercept. It's where the equation intersects with the y line. Since the original equation didn't have one, it means it passed through the origin and now that it has one, the intersection would be (0,1). Because of this, the whole equation would shift up 1 whole unit.

When the function f(x) = 6(9)x is changed to f(x) = 6(9)x + 1,

the y -intercept is 1 space higher.

What is a function?

  • "A relationship is a relationship between input and output."
  • "In a function, there is exactly one output for each input."

What is the slope-intercept form of the line?

The slope-intercept form of the line is y = mx + c

where 'm' is the slope and 'c' is the y-intercept.

What is y-intercept?

"The point where the graph of the function intersects the y-axis"

For given question,

We have been given a function f(x) = 6(9)x

The function is changes to f(x) = 6(9)x + 1

Assuming f(x) = y,

Given function is of the form y = mx + c

The y-intercept for f(x) = 6(9)x is 0.

When function is changed to f(x) = 6(9)x + 1

For this function, the value of y-intercept is 1.

Therefore, when the function f(x) = 6(9)x is changed to f(x) = 6(9)x + 1, the y-intercept is 1 space higher.

Learn more about the function here:

brainly.com/question/13581879

#SPJ2

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE

Otras preguntas