Respuesta :
The magnitude of a vector is simply the Pythagorean Theorem!
[tex] \sqrt{a^2+b^2} = magnitude[/tex]
a=8, b=-6
[tex] \sqrt{8^2+(-6)^2} = magnitude[/tex]
magnitude = 10
Unit vector: (8/10, -6/10).
Divide by 10!(magnitude)
[tex] \sqrt{a^2+b^2} = magnitude[/tex]
a=8, b=-6
[tex] \sqrt{8^2+(-6)^2} = magnitude[/tex]
magnitude = 10
Unit vector: (8/10, -6/10).
Divide by 10!(magnitude)
Answer:
The magnitude is 10 units.
Step-by-step explanation:
we have to find the magnitude of vector and also vector as the sum of unit vectors.
The magnitude of a vector is simply the Pythagorean Theorem
[tex]\sqrt{a^2+b^2} = ||(a,b)||[/tex]
a=8, b=-6
[tex]\sqrt{8^2+(-6)^2} = ||(8,-6)||[/tex]
[tex]magnitude = \sqrt{64+36}=\sqrt{100}=10 units[/tex]
The unit vector is
[tex]<8,-6>=<\frac{8}{10},\frac{-6}{10}>[/tex]
And in unit vector form, we have:
[tex]<8,-6>=8\hat{i}-6\hat{j}[/tex]
