What is the inverse of h?
h(x) = 6x + 1

A) h^-1(x) = 6x - 1
B) h^-1(x) = 6x + 1
C) h^-1(x) = x/6 - 1
D) h^-1(x) = 1/6 (x - 1)

to find the inverse of f(x),,

replace f(x) with y
switch x and y
solve for y
replae y with f infverse or f^-1(x)

h(x)=6x+1
replace
y=6x+1
switch
x=6y+1
solve
x-1=6y
(x-1)/6=y
replace
h^-1(x)=(x-1)/6

D is answer

Answer Link

RenatoMattice RenatoMattice · Answer 2 · 2018-12-19T06:35:14+01:00

RenatoMattice RenatoMattice

19-12-2018

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

[tex]h(x)=6x+1\\[/tex]

We need to find the inverse of h .

Let,

[tex]h(x)=y[/tex]

the our equation becomes,

[tex]y=6x+1\\\\y-1=6x\\\\\frac{y-1}{6}=x[/tex]

Now, interchange x with y :

[tex]\frac{x-1}{6}=y[/tex]

so, our inverse of h will be

[tex]h^{-1}(x)=\frac{x-1}{6}[/tex]

Hence, Option 'D' is correct.

Answer Link

What is the inverse of h? h(x) = 6x + 1 A) h^-1(x) = 6x - 1 B) h^-1(x) = 6x + 1 C) h^-1(x) = x/6 - 1 D) h^-1(x) = 1/6 (x - 1)

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Otras preguntas

What is the inverse of h?
h(x) = 6x + 1

A) h^-1(x) = 6x - 1
B) h^-1(x) = 6x + 1
C) h^-1(x) = x/6 - 1
D) h^-1(x) = 1/6 (x - 1)