Molarity = mol/L
density= grams/ mL
this is a conversion problem where we have to change the numerator from grams to moles, and the denominator from ml to L.
First, we need our conversion factors
1 liters= 1000 mililters
to convert the mass to moles, we need the molar mass of the compound acetic acid (CH3COOH)
molar mass of CH3COOH is 60.05 g/mol, which can be calculated by going to the periodic table and add the mass of the each atom in the compound formula.
1.049 g/ ml (1 mol/ 60.05 grams)= 0.0175 mol/ ml
0.0175 mol/ ml (1000 ml/ 1 liters)= 17.5 mol/ L or 17.5 M
