A 440 kg roller coaster car is going 26 m/s when it reaches the lowest point on the track. If the car started from rest at the top of a hill, how much higher was that point on the track than the lowest point? (Use g = 9.80 m/s2, and ignore friction.)

17 m
23 m
34 m
69 m

Respuesta :

34 m I just took the quiz

Answer: The correct answer is 34.5 m.

Explanation:

The equation of motion is as follows;

[tex]v^{2} -u^{2}= 2as[/tex]

Here, v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance.

It is given in the problem that a car starts from rest at the top of a hill. A 440 kg roller coaster car is going 26 m/s when it reaches the lowest point on the track.

[tex]v^{2} -u^{2}= 2gs[/tex]

Here, g is the acceleration due to gravity.

Put g= 9.80 m/s^2, u=0 and v= 26 m/s.

[tex](26)^{2} -(0)^{2}= 2(9.8)s[/tex]

[tex]s=\frac{676}{19.6}[/tex]

[tex]s= 34.5 m[/tex]

Therefore, the correct answer is 34.5 m.

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