Answer:
[tex]x^\frac{12}{35}[/tex]
Step-by-step explanation:
Here let us first write our expression
It says, x raise to 4 5th power i.e 4 by 5 , again raise to 3 7th power i.e 3 by 7
or [tex](x^{\frac{4}{5}})^\frac{3}{7}[/tex]
Now in this we apply the rule of product of exponents . The rule is like this.
[tex](x^{m})^{n}=x^{mn}[/tex]
Let us apply the rule in our problem
[tex](x^{\frac{4}{5}})^\frac{3}{7} = x^{\frac{4}{5}*\frac{3}{7}}[/tex]
[tex]x^{\frac{4}{5}*\frac{3}{7}} = x^{\frac{4*3}{5*7}}[/tex]
[tex]x^{\frac{4*3}{5*7}}=x^{\frac{12}{35}}[/tex]
Which is x to the 12 over 35 hence our b option is correct
