There are two jars of sweets.
If 20 are taken from the first jar and put into the second, they are in the ratio of 1:2
If 60 are now taken from the second and put into the first, they are in the ratio of 3:1
Work out the original amount in each.

First, we model two equations that satisfy the problem. Let x be the number of sweets in the first jar, and y the number of sweets in the second jar.
First equation:
(x-20)/1 = (y+20)/2
or
(x-20)/(y+20) = 1/2

Second equation:
[(x-20)+60]/3 = [(y+20)-60]/1
or
(x+40) = 3(y-40)

Expressing the first equation in terms of y, we have:
y = 2x - 60

Plugging it in to the second equation:
(x+40) = 3[(2x-60) - 40]
5x = 340
x = 68

y = 2(68)-60 = 76

The first jar originally had 68 sweets and the second jar originally had 76 sweets.

There are two jars of sweets. If 20 are taken from the first jar and put into the second, they are in the ratio of 1:2 If 60 are now taken from the second and put into the first, they are in the ratio of 3:1 Work out the original amount in each.

Respuesta :

Otras preguntas

There are two jars of sweets.
If 20 are taken from the first jar and put into the second, they are in the ratio of 1:2
If 60 are now taken from the second and put into the first, they are in the ratio of 3:1
Work out the original amount in each.