Using quadratic function concepts, it is found that the wider is given by:
D. [tex]Y = 0.3x^2[/tex]
The lower the absolute value of the number that multiplies [tex]x^2[/tex], the wider the parabola is.
- In item A, this value is [tex]\frac{1}{3} = 0.333[/tex]
- In item B, this value is [tex]|-\frac{4}{5}| = |-0.8| = 0.8[/tex]
- In item C, this value is [tex]|-4| = 4[/tex].
- In item D, this value is [tex]|0.3| = 0.3[/tex]
The lowest value is in item D, thus it is the wider parabola.
A similar problem is given at https://brainly.com/question/24705734
