Answer:The equilibrium constant for the given reaction 0.0421.
Explanation:
[tex]PCl_5\rightaleftharpoons PCl_3+Cl_2[/tex]
[tex][PCl_5]=0.0095 M,[PCl_3]=0.020 M,[Cl_2]=0.020 M[/tex]
The equilibrium constant will be given by:
[tex]K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}=\frac{0.020 M\times 0.020M}{0.0095 M}=0.0421[/tex]
The equilibrium constant for the given reaction 0.0421.