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Write an equation and solve. One telephone company charges $16.95 per month and $0.05 per minute for local calls. Another company charges $22.95 per month and $0.02 per minute for local calls. For what number of minutes of local calls per month is the cost of the plans the same?

A. 16.95 + 0.05m = 22.95 + 0.02m; 200 min

B. 16.95 + 0.05m + 22.95 + 0.02m = 0; 570 min

C. 16.95 + 0.05m = 22.95 + 0.02m; 2 min

Respuesta :

corajune99
16.95+.05x=22.95+.02x

Subtract .02x from each side and subtract 16.95 from each side

.03x=6
Divide by .03

x=200 minutes.

Your answer is A

Answer:

The correct option is A. 16.95 + 0.05m = 22.95 + 0.02m; 200 min

Step-by-step explanation:

Consider the provided information.

One telephone company charges $16.95 per month and $0.05 per minute for local calls.

Let m is represents the number of minutes.

Therefore, the cost of plane can be represent as:

[tex]16.95+0.05m[/tex]

Another company charges $22.95 per month and $0.02 per minute for local calls.

Therefore, the cost of plane can be represent as:

[tex]22.95+0.02m[/tex]

Now equate both the equations:

[tex]16.95+0.05m=22.95+0.02m[/tex]

[tex]16.95+0.03m=22.95[/tex]

[tex]0.03m=22.95-16.95[/tex]

[tex]0.03m=6[/tex]

[tex]m=200[/tex]

For 200 minutes the cost of both plans remains the same.

Hence, the correct option is A. 16.95 + 0.05m = 22.95 + 0.02m; 200 min

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