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What is the value of the charge that experiences a force of 2.4 × 10–3 N in an electric field of 6.8 × 10–5 N/C?
A.1.6 × 10–7 C
B.2.5 × 10–3 C
C.2.8 × 10–3 C
D.3.5 × 101 C

Respuesta :

skyluke89

Answer:

D.3.5 × 101 C

Explanation:

The relationship between the force F experienced by a charge of magnitude q in an electric field of strength E is given by

[tex]F=qE[/tex]

In this problem, we know the magnitude of the force ([tex]F=2.4 \cdot 10^{-3}N[/tex] and of the electric field ([tex]E=6.8 \cdot 10^{-5}N/C[/tex]), so we can re-arrange the previous equation to find the magnitude of the charge, q:

[tex]q=\frac{F}{E}=\frac{2.4 \cdot 10^{-3}N}{6.8 \cdot 10^{-5} N/C}=35.2 C=3.5 \cdot 10^1 C[/tex]

samueladesida43

The value of the charge that experiences a force of 2.4 × 10–3 N in an electric field of 6.8 × 10–5 N/C is 3.5 × 10¹C.

HOW TO CALCULATE CHARGE:

  • The relationship between the force experienced by a charge in an electric field can be expressed as follows:

F = qE

Where;

  1. F = Force (N)
  2. q = quantity of charge (C)
  3. E = Strength of electric field (N/C)

According to this question,

  1. F = 2.4 × 10-³ N
  2. q = ?
  3. E = 6.8 × 10-⁵ N/C

q = 2.4 × 10-³ ÷ 6.8 × 10-⁵

q = 0.353 × 10²

q = 3.5 × 10¹ C

Therefore, the value of the charge that experiences a force of 2.4 × 10–3 N in an electric field of 6.8 × 10–5 N/C is 3.5 × 10¹C.

Learn more about charge at: https://brainly.com/question/2292900

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