Respuesta :

Samantha1999
 Ksp = 1.2 x 10^-17 = [Zn2+] [OH-]^2 
Zn(OH)2 <----> Zn2+ + 2OH- 
[Zn2+] = x 
[OH-] = 2x 
1.2 x 10^-17 = (x) ( 2x)^2 = 4 x ^3 
x = 1.4 x 10^-6 M 
2x = 2.8 x 10^-6 M 
pOH = - log 2.8 x 10^-6 = 5.5 
pH = 14 - 5.5 =8.5

i think this is it
Marielena13moe
The ph of a saturates zinc hydroxide solution is 8.64
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