Respuesta :
Answer:
[tex]y=120*(\frac{1}{2})^{\frac{t}{1620}}[/tex]
Step-by-step explanation:
We have been given that Radium-226, a common isotope of radium, has a half-life of 1,620 years.
We will use half life formula to solve our given problem.
[tex]y=a*(\frac{1}{2})^{\frac{t}{h}}[/tex], where,
[tex]a=\text{Initial value}[/tex],
[tex]t=\text{Time}[/tex],
[tex]h=\text{Half life}[/tex].
As we are told that the sample has 120 grams, this means that a equals 120. Upon substituting our given values in half life formula we will get,
[tex]y=120*(\frac{1}{2})^{\frac{t}{1620}}[/tex]
Therefore, the equation [tex]y=120*(\frac{1}{2})^{\frac{t}{1620}}[/tex] represents the remaining amount of Radium-226 after t years.
The equation [tex]y=120*(\frac{1}{2}) ^{\frac{t}{1620} }[/tex] represents the remaining amount of Radium-226 after t years.
Given:
The half-life of a common isotope of radium (Radium-226) = 1,620 years
Initial value (a) = 120 gram
We will use the half-life formula to solve our given problem.
[tex]y=a*(\frac{1}{2} )^{\frac{t}{h} }[/tex]
Where,
a = Initial value
h = Half life
t = Time
So,
[tex]y=120\times(\frac{1}{2}) ^{\frac{t}{h} } \\y=120\times(\frac{1}{2}) ^{\frac{t}{1620} }[/tex]
Therefore, the equation [tex]y=120*(\frac{1}{2}) ^{\frac{t}{1620} }[/tex] represents the remaining amount of Radium-226 after t years.
For more information:
https://brainly.com/question/13135776
