Please help, another math problem! This is all the information it gives me!
1+cos(6x)=

a. 2cos^2(3x)
b. 2sin^2(3x)
c. 3sin(2x)
d. 3cos(2x)

[tex]1 + cos(6x) = 1 + cos(3x + 3x)[/tex]
[tex]= 1 + cos3x cos3x - sin3xsin3x[/tex]
[tex]= 1 + cos^{2}(3x) - sin^{2}(3x)[/tex]
[tex]= 1 + cos^{2}(3x) - (1 - cos^{2}(3x))[/tex]
[tex]= 2cos^{2}(3x)[/tex]

Answer should be (A), to be honest.

Answer Link

ap8997154 ap8997154 · Answer 2 · 2022-08-01T11:43:42+02:00

An expression is defined as a set of numbers, variables, and mathematical operations. The value of the given algebraic expression 1 + cos(6x) can be written as 2cos²(3x). The correct option is A.

What is an Expression?

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

Given the algebraic expression, 1+cos(6x), the value of the expression can be calculated using the algebraic identity cos(2x)= 2cos²(x)-1. Therefore, the value of the expression can be written as,

1 + cos(6x)

= 1 + 2cos²(3x) - 1

= 2cos²(3x)

Hence, the value of the given algebraic expression 1 + cos(6x) can be written as 2cos²(3x).

Learn more about Expression:

https://brainly.com/question/13947055

#SPJ5

Please help, another math problem! This is all the information it gives me! 1+cos(6x)= a. 2cos^2(3x) b. 2sin^2(3x) c. 3sin(2x) d. 3cos(2x)

Respuesta :

What is an Expression?

Otras preguntas

Please help, another math problem! This is all the information it gives me!
1+cos(6x)=

a. 2cos^2(3x)
b. 2sin^2(3x)
c. 3sin(2x)
d. 3cos(2x)