Find the altitude of an isosceles triangle with a vertex angle (that is, the non-base angle) of 70° and a base of 246. Draw a diagram and find the length of the altitude

Respuesta :

altitude = 175.6 units
Ver imagen scarlett24

Answer:

AD=175.66 units

Step-by-step explanation:

It is given that ABC is an isosceles triangle in which base is 246 and the non base angle is 70°.

Thus, applying the angle sum property in ΔABC, we get

∠A+∠B+∠C=180°

⇒70°+2∠B=180°

⇒∠B=55°

Thus, ∠B=∠C=55°.

Now, Draw AD perpendicular to BC such that BD=DC=123, then applying trigonometry in ΔADC, we have

[tex]\frac{AD}{DC}=tan55^{\circ}[/tex]

⇒[tex]\frac{AD}{123}=1.428[/tex]

⇒[tex]AD=123(1.428)[/tex]

⇒[tex]AD=175.66 units[/tex]

Thus, the length of the altitude is 175.66.

Ver imagen boffeemadrid
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