erin46
contestada

What is the equation of a line that is parallel to 2x+3y=-3 and passes through the point (6,1)

Respuesta :

Sbj16
y= -2/3 + 1 im adding additional characters because they jduehe
2x+3y=-3 
3y = -2x - 3
y = -2/3x -1
slope =  -2/3

y = mx +b
1 = -2/3(6) + b
1 = -4 +b
b = 5

equation
y = -2/3x + 5 ...this is your answer


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