Answer: 16
Step-by-step explanation:
The given function : [tex]h(x) = 6 - x[/tex]
We know that for any functions f(x) and g(x)
[tex]f*g (x)=f(x)\times g(x)[/tex]
Therefore , [tex]h*h (x)=h(x)\times h(x)[/tex]
[tex]h*h (x)=(6-x)(6-x)=(6-x)^2[/tex]
[tex]h*h (x)=(6)^2-2(6)(x)+x^2[/tex] [ Using identity [tex](a-b)^2=a^2+2ab+b^2[/tex] ]
[tex]h*h (x)=36-12(x)+x^2[/tex]
[tex]\Rightarrow\ h*h (x)=36-12(x)+x^2[/tex]
Now, at x= 10 , we get
[tex]h*h (10)=36-12(10)+(10)^2[/tex]
[tex]h*h (10)=36-120+100=36+100-120=136-120=16[/tex]
Hence, the value of (h*h)(10) = 16
