Respuesta :
For nuclear reactions, we determine the energy dissipated from the process from the Theory of relativity wherein energy is equal to the mass defect times the speed of light. We calculate as follows:
E = mc^2 = 0.187456 (3x10^8)^2 = 1.687x10^16 J
Hope this answers the question.
E = mc^2 = 0.187456 (3x10^8)^2 = 1.687x10^16 J
Hope this answers the question.
Answer:
[tex]E = 174.6 MeV[/tex]
Explanation:
As we know that energy corresponding to the 1 amu mass is given as
[tex]E = mc^2[/tex]
if m = 1 amu
we have
[tex]E = 931.5 MeV[/tex]
so we will have
mass = 0.187456 amu
[tex]E = (0.187456)(931.5)[/tex]
[tex]E = 174.6 MeV[/tex]
