What you typed is impossible, the greatest possible area for a four sided polygon is a square. If the perimeter is 12, the sides of the square would be 3 inches. The area of that square would be 9 in^2.
Work through this and see that it is impossible.
P=2(W+L), we are told that P=12 so
12=2(W+L)
6=(W+L) and we are told that L=W+1 so
6=2W+1
5=2W
W=2.5, and then L=3.5 so the Area would be:
A=2.5(3.5)= 8.75in^2 NOT 30 in^2
Okay now that that crashed and burned, let's ignore the perimeter statement and just go with L=W+1
Then A=LW and using L=W+1 in the area equation we get:
A=W^2+W and since A=30 we have:
30=W^2+W
W^2+W-30=0
(W+6)(W-5)=0 since W>0 to have any meaning...
W=5 and L=6
Okay that's fine, the area fits the length and width parameters...
Now notice that P=2(5+6)=22in NOT 12 in
:D So you mistyped???
