Given quadratic : [tex]3-4x = 5x^2-14x[/tex].
We need to apply completing the square to solve the equation.
First step is to get rid 4x from left side.
We can add 4x on right side to get rid from left side.
3 = 5x^2-14x+4x
On simplifying this step, we get
3 = 5x^2-10x
Now, we need to factor out 5 from right side to get the coefficient of x^2 as 1.
We get,
3 = 5(x^2-2x)
Now, coefficient of x is -2. So, we need to add half of the square of -2.
-2/2 = -1.
And square of -1 is 1.
Therefore, adding 1 inside parenthesis and 5×1 = 5 on left side, we get
3+5 = 5(x^2 -2x+1)
8 = 5(x^2 -2x+1)
Let us find the perfect square of (x^2 -2x+1).
(x^2 -2x+1) = (x-1)^2
Therefore, we get
8 = 5(x-1)^2.
So, the above highlighted are steps in the process of completing the square.
