historyman historyman

21-03-2017
Mathematics

contestada

If R = 4 in and H = 8 in, what is the approximate surface area of the cylinder?(Use 3.14 for pi.)

A. 226.08 in2

b. 301.44 in2

C. 150.72 in2

D. 401.92 in2

Respuesta :

texaschic101 texaschic101

21-03-2017

SA = 2(pi)rh + 2(pi)r^2
SA = 2(3.14)(4)(8) + 2(3.14)(160
SA = 301.44 in^2

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