Answer: B. 28/45
Step-by-step explanation:
Since, Given numbers of white chips = 8,
Black chips = 2,
Total chips = 8 + 2 = 10,
Thus, the probability of white chip in first drawn = [tex]\frac{8}{10}[/tex]
Now, after replacing one white chip,
Remaining white chips = 8 - 1 = 7,
Total remaining chips = 10 - 1 = 9,
Thus, the probability of white chip in second drawn = [tex]\frac{7}{9}[/tex]
Hence, the probability of randomly choosing a white chip, not replacing it, and then randomly choosing another white chip,
= The probability of white chip in first drawn × The probability of white chip in second drawn
[tex]=\frac{8}{10}\times \frac{7}{9}[/tex]
[tex]=\frac{56}{90}=\frac{28}{45}[/tex]
⇒ Option B is correct.
